(2c+5)(3c^2-4c+2)=

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Solution for (2c+5)(3c^2-4c+2)= equation: 


Simplifying
(2c + 5)(3c2 + -4c + 2) = 0

Reorder the terms:
(5 + 2c)(3c2 + -4c + 2) = 0

Reorder the terms:
(5 + 2c)(2 + -4c + 3c2) = 0

Multiply (5 + 2c) * (2 + -4c + 3c2)
(5(2 + -4c + 3c2) + 2c * (2 + -4c + 3c2)) = 0
((2 * 5 + -4c * 5 + 3c2 * 5) + 2c * (2 + -4c + 3c2)) = 0
((10 + -20c + 15c2) + 2c * (2 + -4c + 3c2)) = 0
(10 + -20c + 15c2 + (2 * 2c + -4c * 2c + 3c2 * 2c)) = 0
(10 + -20c + 15c2 + (4c + -8c2 + 6c3)) = 0

Reorder the terms:
(10 + -20c + 4c + 15c2 + -8c2 + 6c3) = 0

Combine like terms: -20c + 4c = -16c
(10 + -16c + 15c2 + -8c2 + 6c3) = 0

Combine like terms: 15c2 + -8c2 = 7c2
(10 + -16c + 7c2 + 6c3) = 0

Solving
10 + -16c + 7c2 + 6c3 = 0

Solving for variable 'c'.

The solution to this equation could not be determined.

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